Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1051: 103

Answer

$ x=7.5$

Work Step by Step

The given expression $\frac{x}{x-3}=\frac{2x}{x-3}-\frac{5}{3}$ $\begin{align} & \frac{x}{x-3}=\frac{2x}{x-3}-\frac{5}{3} \\ & \frac{x}{x-3}=\frac{6x-5x+15}{3(x-3)} \\ & 3x=6x-5x+15 \\ & 3x=x+15 \end{align}$ $\begin{align} & 2x=15 \\ & x=7.5 \end{align}$
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