Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1050: 96


The statement does not make sense.

Work Step by Step

The given equation is ${{a}_{n}}=\frac{{{\left( -1 \right)}^{2n}}}{3n}$ Now we have $\begin{align} & {{\left( -1 \right)}^{2n}}={{\left\{ {{\left( -1 \right)}^{2}} \right\}}^{n}} \\ & ={{1}^{n}} \\ & =1 \end{align}$ Thus, the sequence will not be an alternative sequence. Therefore, the statement is illogical. Therefore, the statement does not make sense.
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