Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1050: 71



Work Step by Step

Here, we have $6000(1+\dfrac{0.06}{4})^n=8081.13$ Plug $n=20$ Now $6000(1+\dfrac{0.06}{4})^{20}=8081.13$ Hence, the balance is $\$ 8081.13$ after $5$ years.
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