#### Answer

$39,800$

#### Work Step by Step

Write the correct form as below:
We know that $n!=1 \cdot 2 \cdot 3 .....(n-1)n$
Thus, we have $\dfrac{200!}{198!}=\dfrac{1 \cdot 2 \cdot 3 .....198 \cdot 199 \cdot 200}{198!}$
$=\dfrac{(1 \cdot 2 \cdot 3 .....198) \cdot 199 \cdot 200}{198!}$
$=\dfrac{198! \cdot 199 \cdot 900}{198!}$
$=39,800$