Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.7 - Combinations of Functions; Composite Functions - Exercise Set - Page 260: 125


The value of y in the equation $x-{{y}^{2}}=1$ is $y=\sqrt{x+1}$.

Work Step by Step

Solve for the value of y $x={{y}^{2}}-1$ Adding $1$ on both sides of the equation, we get, $x+1=1+{{y}^{2}}-1$ $\begin{align} & x+1={{y}^{2}} \\ & y=\sqrt{x+1} \end{align}$ Hence, the value of y in the equation $x-{{y}^{2}}=1$ is $y=\sqrt{x+1}$.
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