#### Answer

The value of y in the equation $x-{{y}^{2}}=1$ is $y=\sqrt{x+1}$.

#### Work Step by Step

Solve for the value of y
$x={{y}^{2}}-1$
Adding $1$ on both sides of the equation, we get,
$x+1=1+{{y}^{2}}-1$
$\begin{align}
& x+1={{y}^{2}} \\
& y=\sqrt{x+1}
\end{align}$
Hence, the value of y in the equation $x-{{y}^{2}}=1$ is $y=\sqrt{x+1}$.