Answer
The value of y in the equation $Ax+By=Cy+D$ is $\frac{D-Ax}{B-C}$.
Work Step by Step
Collect all the y terms on the left side of the equation and the other terms of the equation on the right side.
$Ax+By-Cy=D$
Factor y on the left side of the equation and get
$y\left( B-C \right)=D-Ax$
Dividing both sides by $B-C$, we get,
$\begin{align}
& y\frac{\left( B-C \right)}{\left( B-C \right)}=\frac{D-Ax}{B-C} \\
& y=\frac{D-Ax}{B-C}
\end{align}$
Hence, the value of y in the equation $Ax+By=Cy+D$ is $\frac{D-Ax}{B-C}$.
