Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set: 36

Answer

$y-0=-\frac{3}{2}(x+1)$ $y=-\frac{3}{2}x-\frac{3}{2}$

Work Step by Step

$m$=$(0-(-3))\div(-1-1)$ $m=(3)\div(-2)$ $m=-\frac{3}{2}$ $y−0=-\frac{3}{2}\times(x−(-1))$ $y-0=-\frac{3}{2}(x+1)$ $y=-\frac{3}{2}(x+1)$ $y=-\frac{3}{2}x+(-\frac{3}{2})1$ $y=-\frac{3}{2}x-\frac{3}{2}$
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