#### Answer

point-slope form: $y-3 = 4(x-1)$
slope-intercept form: $y=4x-1$

#### Work Step by Step

RECALL:
(1) The slope-intercept form of a line's equation is:
$y=mx+b$
where m = slope and b = y-intercept
(2) The point-slope form of a line's equation is:
$y-y_1=m(x-x_1)$
(a) point-slope form
The given line has a slope of $4$ and passes through the point $(1, 3)$.
Substitute these values into the point-slope form above to obtain:
$y-3=4(x-1)$
(b) slope-intercept form
Substitute the slope 4 to $m$ to obtain the tentative equation:
$y=4x+b$
The line passes through $(1, 3)$.
This means that the coordinates of this point satisfy the equation of the line. Substitute the x and y-coordinates of this point into the tentative equation to obtain:
$y=4x+b
\\3 = 4(1) + b
\\3 = 4 + b
\\3-4 = b
\\-1 = b$
Thus, the equation of the line is $y=4x-1$.