Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set - Page 213: 32

Answer

$y+2=-\frac{4}{3}\times(x−3)$ $y=-\frac{4}{3}x+2$

Work Step by Step

$m$=$(-2-6))\div(3−(−3))$ $m=(-8)\div(3+3)$ $m=\frac{-8}{6}$ $m=-\frac{4}{3}$ $y−(-2)=-\frac{4}{3}\times(x−3)$ $y+2=-\frac{4}{3}\times(x−3)$ $y+2=-\frac{4}{3}x+\frac{4}{3}\times3$ $y+2=-\frac{4}{3}x + 4$ $y=-\frac{4}{3}x+2$
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