Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.4 - Linear Functions and Slope - Exercise Set: 31

Answer

$y−6=\frac{4}{3}(x−3)$ $y=\frac{4}{3}x+2$

Work Step by Step

$m$=$(6−(-2))\div(3−(−3))$ $m=(6+2)\div(3+3)$ $m=\frac{8}{6}$ $m=\frac{4}{3}$ $y−6=\frac{4}{3}\times(x−3)$ $y−6=\frac{4}{3}x−\frac{4}{3}\times3$ $y-6=\frac{4}{3}x - 4$ $y=\frac{4}{3}x+2$
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