Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 180: 134



Work Step by Step

From the given expression, we have $2(x+h)^2+3(x+h)+5-(2x^2+3x+5)=2x^2+4xh+2h^2+3x+3h+5-2x^2-3x-5=4xh+2h^2+3h$
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