Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.2 - Basics of Functions and Their Graphs - Exercise Set - Page 180: 129


The value of x is 13. Yes, $x=13$ satisfies the given equation.

Work Step by Step

Solve for x: $\begin{align} & -1+3\left( x-4 \right)=2x \\ & -1+3x-12=2x \\ & 3x-13=2x \\ & 3x-2x=13 \\ & x=13 \end{align}$ Now, putting $x=13$ in the equation, we check whether LHS and RHS come out to be the same or not. $\begin{matrix} -1+3\left( x-4 \right)=2x \\ -1+3\left( 13-4 \right)\overset{?}{\mathop{=}}\,2\left( 13 \right) \\ -1+3\left( 9 \right)\overset{?}{\mathop{=}}\,26 \\ -1+27\overset{?}{\mathop{=}}\,26 \\ 26=26 \\ \end{matrix}$ Therefore, the value of x obtained is correct. Thus, the value of x for the given equation is 13. The value of $x=13$ satisfies the given equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.