## Precalculus (6th Edition) Blitzer

The value of x is 13. Yes, $x=13$ satisfies the given equation.
Solve for x: \begin{align} & -1+3\left( x-4 \right)=2x \\ & -1+3x-12=2x \\ & 3x-13=2x \\ & 3x-2x=13 \\ & x=13 \end{align} Now, putting $x=13$ in the equation, we check whether LHS and RHS come out to be the same or not. $\begin{matrix} -1+3\left( x-4 \right)=2x \\ -1+3\left( 13-4 \right)\overset{?}{\mathop{=}}\,2\left( 13 \right) \\ -1+3\left( 9 \right)\overset{?}{\mathop{=}}\,26 \\ -1+27\overset{?}{\mathop{=}}\,26 \\ 26=26 \\ \end{matrix}$ Therefore, the value of x obtained is correct. Thus, the value of x for the given equation is 13. The value of $x=13$ satisfies the given equation.