## Precalculus (6th Edition) Blitzer

The value of x is $x=-12$
Let us consider the equation $\frac{x-3}{5}-\frac{x-4}{2}=5$. Then \begin{align} & \frac{2x-6-5x+20}{10}=5 \\ & -3x+14=50 \\ & -3x=36 \\ & x=-12 \end{align} Put the value of x in the equation. Thus \begin{align} & \frac{\left( -12 \right)-3}{5}-\frac{\left( -12 \right)-4}{2}=5 \\ & \frac{-15}{5}-\frac{\left( -16 \right)}{2}=5 \\ & -3+8=5 \\ & 5=5 \end{align} Hence, the value of x is checked. Hence, $x=-12$