Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 303: 91


The domain of the function $f\left( x \right)={{x}^{2}}+6x-3$ is $f=\left( -\infty,\infty \right)$.

Work Step by Step

Consider the given function $f\left( x \right)={{x}^{2}}+6x-3$. We can see that this function contains neither division nor the square root. Also, the expression ${{x}^{2}}+6x-3$ represents a real number, for every value of $x$. Therefore, the domain of the given function is the set of all real numbers. Therefore, the domain of the function $f\left( x \right)={{x}^{2}}+6x-3$ is $f=\left( -\infty,\infty \right)$.
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