Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 303: 102

Answer

a. $(f\circ g)(x)=\frac{1+x}{1-2x}$ b. $(-\infty,0)\cup(0,\frac{1}{2})\cup(\frac{1}{2}, \infty)$

Work Step by Step

a. Given $f(x)=\frac{x+1}{x-2}, x\ne2$ and $g(x)=\frac{1}{x}, x\ne0$, we have $(f\circ g)(x)=\frac{1/x+1}{1/x-2}=\frac{1+x}{1-2x}$ b. The domain of $(f\circ g)(x)$ can be found as $(-\infty,0)\cup(0,\frac{1}{2})\cup(\frac{1}{2}, \infty)$
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