Answer
a. $(f\circ g)(x)=\sqrt {x+2}$
b. $[-2, \infty)$
Work Step by Step
a. Given $f(x)=\sqrt {x-1}, x\geq1$ and $g(x)=x+3$, we have $(f\circ g)(x)=\sqrt {x+3-1}=\sqrt {x+2}$
b. The domain of $(f\circ g)(x)$ can be found as $[-2, \infty)$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 1 - Review Exercises - Page 303: 103
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