Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Review Exercises - Page 303: 69

Answer

a. $32\ ft/sec$ b. $-32\ ft/sec$ c. upward motion, downward motion.

Work Step by Step

a. Using the given equation, we have $s(0)=80\ ft$ and $s(2)=-16(2)^2+64(2)+80=144\ ft$. Thus the average velocity for this time interval can be found as $\bar v_1=\frac{144-80}{2-0}=32\ ft/sec$ b. We have $s(4)=-16(4)^2+64(4)+80=80\ ft$. Thus the average velocity for this time interval can be found as $\bar v_2=\frac{80-144}{4-2}=-32\ ft/sec$ c. The result from part-a is positive, indicating an upward motion. The result from part-b is negative, indicating a downward motion.
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