Answer
$19.5^\circ, 70.5^\circ$
Work Step by Step
Given $c=3in, a=1in$, we have $A=sin^{-1}\frac{a}{c}=sin^{-1}\frac{1}{3}\approx19.5^\circ$ and $B=90^\circ-A \approx70.5^\circ$
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