Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 8 - Applications of Trigonometric Functions - 8.1 Right Triangle Trigonometry; Applications - 8.1 Assess Your Understanding - Page 519: 44

Answer

$19.5^\circ, 70.5^\circ$

Work Step by Step

Given $c=3in, a=1in$, we have $A=sin^{-1}\frac{a}{c}=sin^{-1}\frac{1}{3}\approx19.5^\circ$ and $B=90^\circ-A \approx70.5^\circ$
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