Answer
$c \approx5.83, A \approx59.0^\circ, B \approx31.0^\circ$
Work Step by Step
Given $a=5, b=3$, we have $c=\sqrt {a^2+b^2}=\sqrt {34}\approx5.83, A=tan^{-1}\frac{a}{b}=tan^{-1}\frac{5}{3}\approx59.0^\circ, B=90^\circ-A\approx31.0^\circ$
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