Answer
$c \approx8.25, A \approx14.0^\circ, B \approx76.0^\circ$
Work Step by Step
Given $a=2, b=8$, we have $c=\sqrt {a^2+b^2}=\sqrt {68}\approx8.25, A=tan^{-1}\frac{a}{b}=tan^{-1}\frac{2}{8}\approx14.0^\circ, B=90^\circ-A\approx76.0^\circ$
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