Answer
$b \approx7.15, B= 50^\circ,
c \approx9.33$
Work Step by Step
Given $a=6, A=40^\circ$, we have $b=a\ cotA=6cot40^\circ\approx7.15, B=90^\circ-40^\circ=50^\circ,
c=\frac{a}{sinA}=\frac{6}{sin40^\circ} \approx9.33$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 8 - Applications of Trigonometric Functions - 8.1 Right Triangle Trigonometry; Applications - 8.1 Assess Your Understanding - Page 519: 36
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