Answer
False.
Work Step by Step
We know that $\sin{(\theta)}=\cos(90^{o}-\theta)$, hence $\sin{(52^{o})}=\cos{(90^{o}-52^{o})}=\cos{(38^{o})}.$ Hence it is false.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 8 - Applications of Trigonometric Functions - 8.1 Right Triangle Trigonometry; Applications - 8.1 Assess Your Understanding - Page 519: 4
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