Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 507: 80



Work Step by Step

I know that $\cot x=\frac{1}{\tan(x)}$, hence $\cot^{-1}x=\tan^{-1} \frac{1}{x}$. I use a calculator in radian mode and then round the result, hence: $\cot^{-1}{(-4)}=\tan^{-1}{-\frac{1}{4}}=-0.2450\approx-0.25.$
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