Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 507: 64

Answer

$ \frac{\pi}{3}, \frac{5\pi}{3}$

Work Step by Step

Step 1. $cos\theta=\frac{1}{2} \longrightarrow \theta=2k\pi+\frac{\pi}{3}$ and $\theta=2k\pi+\frac{5\pi}{3}$ Step 2. Within $[0,2\pi)$, we have $\theta= \frac{\pi}{3}, \frac{5\pi}{3}$
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