Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 507: 79



Work Step by Step

I know that $\sec x=\frac{1}{\cos(x)}$, hence $\sec^{-1}x=cos^{-1} \frac{1}{x}$. I use a calculator in radian mode and then round the result, hence: $\sec^{-1}{(3)}=\cos^{-1}{\frac{1}{3}}=1.2310\approx1.23.$
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