Answer
$0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}$
Work Step by Step
Step 1. $tan(2\theta)=0 \longrightarrow 2\theta=k\pi \longrightarrow \theta=\frac{k\pi}{2}$
Step 2. Within $[0,2\pi)$, we have $\theta=0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 507: 67
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