Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - Chapter Review - Review Exercises - Page 507: 66

Answer

$\frac{3\pi}{4}, \frac{7\pi}{4}$

Work Step by Step

Step 1. $sin(2\theta)=-1 \longrightarrow 2\theta=2k\pi+\frac{3\pi}{2} \longrightarrow \theta=k\pi+\frac{3\pi}{4}$ Step 2. Within $[0,2\pi)$, we have $\theta=\frac{3\pi}{4}, \frac{7\pi}{4}$
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