Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 9

Answer

$24$

Work Step by Step

We know that $P(n,r)=\dfrac{n!}{(n-r)!}.$ Hence, $P(4,4)=\dfrac{4!}{(4-4)!}=\dfrac{4\cdot3\cdot2\cdot1}{0!}=4\cdot3\cdot2\cdot1=24$
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