Answer
$40320$
Work Step by Step
We know that $P(n,r)=\dfrac{n!}{(n-r)!}$ and $0!=1$.
Hence,
$P(8,8)=\dfrac{8!}{(8-8)!}=\dfrac{8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{0!}=8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=40320$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 10
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