Answer
$120$
Work Step by Step
The number of ways of arranging $n$ distinct objects is $n!=n\cdot(n-1)\cdot(n-2)\cdot...\cdot3\cdot2\cdot1.$
Here, we have $n=5$. Hence, the number of possible arrangements is
$5!=5\cdot4\cdot3\cdot2\cdot1=120$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 45
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