Answer
$28$
Work Step by Step
We know that $C(n,r)=\dfrac{n!}{(n-r)!r!}$. and $C(n,0)=1$.
Hence,
$C(8,2)=\dfrac{8!}{(8-2)!\cdot2!}=\dfrac{8\cdot7\cdot6!}{6!\cdot2\cdot1}=\dfrac{8\cdot7}{2}=28$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 15
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