Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 13 - Counting and Probability - 13.2 Permutations and Combinations - 13.2 Asses Your Understanding - Page 855: 21

Answer

$10,400,600$

Work Step by Step

We know that $C(n,r)=\dfrac{n!}{(n-r)!r!}$ and $C(n,0)=1$. Hence, $C(26,13)=\dfrac{26!}{(26-13)!\cdot13!}=\dfrac{26!}{13!\cdot13!}=10,400,600$. (With the help of a calculator.)
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