Answer
$(d)$
Work Step by Step
The standard equation for a circle with radius $r$ and center $(h,k)$ is:
$(x-h)^2+(y-k)^2=r^2$
Hence, a circle whose center is at $(3, -5)$ and whose radius is $6$ has the standard equation:
$(x-3)^2+[y-(-5)]^2=6^2
\\(x-3)^2+(y+5)^2=36$
Thus, the answer is Option $(d)$.
