## Precalculus (10th Edition)

$(d)$
The standard equation for a circle with radius $r$ and center $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$ Hence, a circle whose center is at $(3, -5)$ and whose radius is $6$ has the standard equation: $(x-3)^2+[y-(-5)]^2=6^2 \\(x-3)^2+(y+5)^2=36$ Thus, the answer is Option $(d)$.