Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.4 Circles - 1.4 Assess Your Understanding - Page 38: 7



Work Step by Step

The standard equation for a circle with radius $r$ and center $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$ Hence, a circle whose center is at $(3, -5)$ and whose radius is $6$ has the standard equation: $(x-3)^2+[y-(-5)]^2=6^2 \\(x-3)^2+(y+5)^2=36$ Thus, the answer is Option $(d)$.
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