Answer
(a) $(\frac{1}{2},-1)$, $\frac{1}{2}$. (b) see graph. (c) $(0,-1)$
Work Step by Step
(a) Given $x^2+y^2-x+2y+1=0$, form squares to get $(x-\frac{1}{2})^2+(y+1)^2=\frac{1}{4}$. We can identify its center $(h,k)=(\frac{1}{2},-1)$ and radius $r=\frac{1}{2}$.
(b) see graph.
(c) We can find the x-intercepts ($none$). The y-intercept is $(0,-1)$
