Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 1 - Graphs - 1.4 Circles - 1.4 Assess Your Understanding - Page 38: 38

Answer

$(x-1)^2+(y-0)^2=\sqrt{20}$.

Work Step by Step

The general equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$. The distance formula from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$. Hence here: $r=\sqrt{(1-(-3))^2+(0-2)^2}=\sqrt{16+4}=\sqrt{20}.$ Also $C=(1,0)$, hence our equation: $(x-1)^2+(y-0)^2=\sqrt{20}$.
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