## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$=1,000$
Using the fact that $\frac{a^m}{a^n}=a^{m-n}$, this expression becomes $$\frac{10^8}{10^5}=10^{8-5}=10^3=10^2(10)=100\cdot10=1,000$$