#### Answer

$\pm r^2$

#### Work Step by Step

Use the fact that $\sqrt{a}=a^\frac{1}{2}$ along with the fact that $(a^b)^n=a^{bn}$ to get $$\sqrt{r^4}=r^{\frac{4}{2}}=r^2$$ However, $(-r^2)(-r^2)=r^4$ also. So, $\pm r^2$ is the result.

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Published by
Wiley

ISBN 10:
1118583191

ISBN 13:
978-1-11858-319-7

$\pm r^2$

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