## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$=16$
Using the fact that $\frac{a^m}{a^n}=a^{m-n}$, the expression can be rewritten as $$\frac{2^7}{2^3}=2^{7-3}=2^4=(2^2)(2^2)=4(4)=16$$