## Functions Modeling Change: A Preparation for Calculus, 5th Edition

$w^4z^2$
First, use the fact that $\sqrt{a}=a^\frac{1}{2}$ to simplify the expression to $(w^8z^4)^\frac{1}{2}$ It's also known that $(a^b)^n=a^{bn}$ and that $(ab)^n=a^nb^n$, so the expression can be simplified to $$=w^\frac{8}{2}z^\frac{4}{2}=w^4z^2$$