Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 4 - Exponential Functions - Exercises to Skills for Chapter 4 - Page 185: 36



Work Step by Step

First, use the fact that $\sqrt{a}=a^\frac{1}{2}$ to simplify the expression to $(w^8z^4)^\frac{1}{2}$ It's also known that $(a^b)^n=a^{bn}$ and that $(ab)^n=a^nb^n$, so the expression can be simplified to $$=w^\frac{8}{2}z^\frac{4}{2}=w^4z^2$$
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