Answer
A) Exponential
B) $h(x)=14(0.9)^x$
Work Step by Step
Given
$$
\begin{array}{c|c}
\hline x & h(x) \\
\hline 0 & 14 \\
1 & 12.6 \\
2 & 11.34 \\
3 & 10.206 \\
4 & 9.185 \\
\hline
\end{array}
$$
A) We know that a function is linear if the differences of successive values of the function is a constant. A function is exponential if the ratios of successive values of the function is a constant.
$$
\begin{aligned}
&h(1)-h(0)=12.6-14=-1.4\\
&h(2)-h(1)=11.34-12.6=-1.26
\end{aligned}
$$
Thus, the function is not linear. The ratios gives
$$
\begin{aligned}
& \frac{h(1)}{h(0)}=0.9 \\
& \frac{h(2)}{h(1)}=\frac{11.34}{12.6}=0.9 .
\end{aligned}
$$
Hence, the function is exponential.
B) We know that
$$
h(x)=ab^x
$$
Thus,
$$
\begin{aligned}
& 14=h(0) \\
& 14=a b^0 \\
& 14=a .
\end{aligned}
$$
$$
\begin{aligned}
& 12.6=h(1) \\
& 12.6=14 b\\
&b=\frac{12.6}{14}=0.9
\end{aligned}
$$ Hence:
$$
h(x)=14(0.9)^x
$$