Answer
$
f(x)=10\cdot\left(\sqrt[3]2\right)^x
$
Work Step by Step
We want to have $f(x)=a b^{x}$.
The graph shows that the points $(0,10),(3,20)$ lie on the curve of $f(x)$.
We must have $f(0)=a b^{0}=a= 10$ and so $f(x)=10 b^{x}$.
But $f(3)=10 b^{3}= 20\implies b= 2^{1/3}= \sqrt[3]2\approx 1.26 $
It follows that $$
f(x)=10\cdot\left(\sqrt[3]2\right)^x\approx 10\cdot\left(1.26\right)^x
$$