Functions Modeling Change: A Preparation for Calculus, 5th Edition

Published by Wiley
ISBN 10: 1118583191
ISBN 13: 978-1-11858-319-7

Chapter 2 - Functions - 2.5 Preview of Composite and Inverse Functions - Exercises and Problems for Section 2.5 - Exercises and Problems - Page 102: 25

Answer

$$A =\sqrt{\frac{r}{\pi}}$$

Work Step by Step

Finding the inverse by switching the dependent and independent variables, we find: $$ r = \pi A^2 \\ A =\sqrt{\frac{r}{\pi}}$$
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