Answer
$
g\left(\frac{3}{2}\right)=\frac{23}{4}
$
$g^{-1}(-17)=-2$
Work Step by Step
We have
$$
g\left(\frac{3}{2}\right)=2\left(\frac{3}{2}\right)^3-1=\frac{23}{4}
$$
If $-17=2 x^3-1$, then $x^3=-8$, so $x=-2$. Thus, $g^{-1}(-17)=-2$.
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