Answer
$
k(3)=2 ,
$
$k^{-1}(14)=6$
Work Step by Step
We have
$$
k(3)=4(3)-10=12-10=2 .
$$
To find $k^{-1}(14)$, we find the value of $x$ so that $k(x)=14$. If $14=4 x-10$, then $24=4 x$ so $x=6$. Thus, $k^{-1}(14)=6$.
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