Answer
$f(g(2))=-10$
Work Step by Step
First, find $g(2)$ by inserting $x=2$ into $g(x)$ to get $g(2)=1-2^2=1-4=-3$. Next, use $g(2)$ as $x$ in $f(x)$ to get $f(g(2))=f(3)=3(-3)-1=-10$.
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