Answer
$g(f(x))=-9 x^2+6 x$
Work Step by Step
Given $f(x)=3 x-1$ and $g(x)=1-x^2$, we have
$g(f(x))=g(3 x-1)=1-(3 x-1)^2=1-\left(9 x^2-6 x+1\right)=-9 x^2+6 x$
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