## Prealgebra (7th Edition)

$A=2.5^2\pi=6.25\pi\approx 6.25\times\frac{22}{7}\approx19.643$ square m.
The area of the circle can be calculated as: $A=r^2\pi$ where r is the radius. Here: $d=5$ m $r=2.5$ m $A=2.5^2\pi=6.25\pi\approx 6.25\times\frac{22}{7}\approx19.643$ square m.