#### Answer

$T=45$ square in.

#### Work Step by Step

The area of this figure can be calculated as the sum of the area of the square and the area of the parallelogram.
$T=T_1+T_2$
Square:
$T_1=a^2$
$T_1=5^2=25$ square in.
Parallelogram:
$T_2=h\times a=4\times 5=20$ square in
$T=T_1+T_2=25+20=45$ square in.