Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Exercise Set - Page 634: 19


$T=25$ square cm.

Work Step by Step

The area of this figure can be calculated as the sum of the rectangle and the triangle on the top. $T=T_1+T_2$ Rectangle: $T_1=a\times b$ $T_17\times 3=21$ square cm. Triangle: $h\times \frac{a}{2}=2\times \frac{7-2\times1\frac{1}{2}}{2}=7-3=4$ square cm $T=T_1+T_2=21+4=25$ square cm.
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