## Prealgebra (7th Edition)

$T=82$ square km.
The area of this figure can be calculated as the sum of the area of the rectangle and the area of the trapezoid on the top. $T=T_1+T_2$ Rectangle: $T_1=a\times b$ $T_1=10\times5=50$ square km. Trapezoid: $T_2=h\times \frac{a+c}{2}=4\times \frac{6+10}{2}=4\times 8=32$ square km $T=T_1+T_2=50+32=82$ square km.